Question

How many atoms are there in 3 moles of calcium?

Answer 1

Answer:

39.10 grams is the molar mass of one mole of K. Grams can be canceled, leaving the moles of K. How many grams is in 10.00 moles of calcium (Ca)? The number of atoms can also be calculated using Avogadro's Constant (6.02214179×1023) / one mole of substance.

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Answer 2

Answer:

$1.927*10^{24}$

Explanation:

1 mole of any material contains the Avogadro number of particles, that is, 6.023*10^23 particles.

Hence, by ratio and proportion, #3.2# moles of calcium will contain #3.2 xx 6.023xx10^23# Ca particles or atoms, which is #1.927xx10^24# Ca atoms.

The Avogadro constant, generally abbreviated NA[1] or L[2], is the proportionality factor that connects the quantity of material in a sample with the number of constituent particles (typically molecules, atoms, or ions) in that sample. It has a precise value of 6.022140761023 reciprocal moles and serves as a SI defining constant. [3] [4] Stanislao Cannizzaro named it after the Italian mathematician Amedeo Avogadro[5], who described this number at the Karlsruhe Congress in 1860, four years after Avogadro's passing. [6]

The Avogadro number is a dimensionless number that represents the Avogadro constant as a numerical value given in reciprocal moles. The Avogadro number, or precisely 6.022140761023, is written as N[7][8] or N0,[9][10] in earlier literature. This number represents the number of particles that make up one mole. [3]

This is the Avogadro number:

the approximate number of nucleons (protons and neutrons) in one gram of ordinary matter. The value of the Avogadro constant was chosen so that the mass of one mole of a chemical compound, expressed in grams, is approximately the number of nucleons in one constituent particle of the substance.

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