how many atoms are there in 32g CH4
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Answer:
Explanation:
no. of atoms= no. of moles* avogadro number
avogadro number=6.023* 10^23
no. of moles=weight in grams/molar mass
weight=32g
molar mass=12+1*4=16
therefore,no. of moles=32/16=2
therefore, no. of particles=2*6.023*10^23=12.046*10^23
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