Question

How many atoms are there in 40g of sulphur .​

Answer 1

Answer:

$32 g \: of \: sulphur \: have \: 6.022 \times {10}^{23} atoms \\ then \: 1 \: g \: sulphur \: must \: have \: \frac{6.022 \times {10}^{23} }{32} atoms \\ so \: 40 \: g \: of \: sulphur \: should \: have \: \frac{40 \times 6.022 \times {10}^{23} }{32} \\ = 7.52 \times {10}^{23 } \: atoms \: of \: sulphur \:$

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Answer 2

Answer:

Number of atoms in 40g of Sulfur is 7.512240760954312 x 10^23 atoms

Explanation:

To calculate the number of atoms in any element, one has to know the MOLAR MASS of that element.

MOLAR MASS  is predefined. Every element has its molar mass predefined and if the question asks the number of atoms, Molar mass is usually provided in question itself.

STEPS

Get the molar mass, in this case, MOLAR MASS of sulfur is 32.065 u

Divide the quantity i.e. 40g by 32.065 u

And then multiply it with Avogadro number i.e. 6.022 X 10^23.

• Why do we use Avogadro number ?

Because, Avogadro number tells us the number of particles in 1 mole.

hope it helps

jerri