Question

how many atoms are there in 65.89 g of lead?

Answer 1

Answer:

Molar mass of lead = 207.2 g/mol

Moles of lead in 1kg:

1000g / 207.2 g/mol = 4.83mol

Atoms in 4.83 moles:

4.83mol x 6.02 x 10^23 = 4.11 x 10^18 atoms

Answer 2

There are $1.91 \times 10^{23}$ atoms present in 65.89 g of lead.

Explanation:

According to the mole concept, there are $6.022 \times 10^{23}$ atoms present in 1 mole of a substance.

As molar mass of lead is 207.2 g/mol and its mass is given as 65.89 g. Therefore, calculate its number of moles as follows.

         No. of moles = $\frac{mass}{\text{molar mass}}$

                               = $\frac{65.89 g}{207.2 g/mol}$

                               = 0.318 mol

Hence, number of atoms present in 0.318 mol are as follows.

      No. of atoms = $0.318 mol \times 6.022 \times 10^{23}$

                             = $1.91 \times 10^{23}$ atoms

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