how many atoms are there in 68 gram of NH3?
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Answered by
5
Answer:
Explanation:Molar mass of NH3 =17
Given mass =68
So,number of moles of NH3= GIVEN MASS/molar mass
therefore 68/17= 4
So number of atoms of NH3 = no. Of moles× avogadro no.
4×6.022×10^23= 24.088×10^23
Or 2.4088×10^24
Answered by
4
To get the atoms our first approach will be to calculate moles
Moles = given mass÷molar mass
=68÷17=4
Now total atoms are atoms of nitrogen and atoms of hydrogen ie 4 atoms
Total atoms = moles ×4 × 6.02×10^3
Hope this is helpful to u
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