Question

How many atoms constituite 1 unit cell of fcc?

Answer 1

⭐《ANSWER》

$\huge\mathfrak{\underline {\underline\pink {ANSWER}}}$

↪Actually welcome to the concept of the SOLID STATE

↪Basically here we can see that , the given lattice is a

↪FACE CENTRED CUBIC

↪Now we have to know that , in any primary lattice ,

↪at coners , the atoms share 1/8 of total structure and at the adjacent or opposite faces , they atoms make share of 1/2 of total atom

↪so in the FCC , TYPE we have 8 Corners and 6 faces , so if we calculate the total number of atoms constitute here , we get as

↪CORNERS ==》 1/8 * 8 = 1atoms at corner

↪FACES ==》 1/2 * 6 = 3 atoms at face

〽so total Atoms in the FCC are , 3+1= 4 atoms