Question

how many atoms do mercury vapour molecules consists of if the density of mercury vapour relative to air is 6.92(Hg = 200).The average mass of air is 29g/mole.​

Answer 1

Answer : The number of atoms of mercury vapor molecule contains, 1

Explanation :

Let us consider the atomicity of mercury in vapor state be, 'x'. And its molecular formula is expressed as, $Hg_x$.

As we are given that,

$\frac{D_{Hg_x}}{D_{Air}}=6.92$

where,

$D_{Hg_x}$ = density of mercury vapor

$D_{Air}$ = density of air

Or,

$\frac{M_{Hg_x}}{M_{Air}}=6.92$

where,

$M_{Hg_x}$ = mass of mercury vapor = $[200\times (x)]g/mole$

$M_{Air}$ = mass of air = 29 g/mole

Now put all the given values in this expression, we get the value of 'x'.

$\frac{200\times (x)}{29}=6.92$

$x=1.00=1$

Therefore, the number of atoms of mercury vapor molecule contains, 1

Answer 2

Answer:

1 atom

Explanation:

For explanation, please refer to the attachment given.

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