how many atoms of c are present in 4.40 of co2
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Answered by
1
Mole= given mass/molecular weight
=4.40/44=0.1
number of molecules =mole •Avogadro number
=0.1•NA
number of C atom=0.1•6.02•10²³•1
=6.02•10²²
=4.40/44=0.1
number of molecules =mole •Avogadro number
=0.1•NA
number of C atom=0.1•6.02•10²³•1
=6.02•10²²
Nistha707:
which is ur answer 1,2or 3
Answered by
0
Heya!
6.02*10^22
Hope this helps.
6.02*10^22
Hope this helps.
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