how many atoms of C,H andO are respectively present in 36 g of glucose ?
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Glucose -- C6 H12 O6
mass = 12 ×6 + 1 ×12 + 16 × 6
= 72 + 12 + 96
= 180
Weight = 36 gm
No. of moles = weight / molecular mass
= 36 / 180
= 1/5
no. of atoms = 6.022 × 10²³ × moles
= 6.022 × 10²³ × 1/5
= 12.044 × 10²²
= 1.2044 × 10²³
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