How many atoms of calcium will be deposited from a solution of cacl2 by current of 25 micro ampere flowing for 60seconds?
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Answer:
144.75 grams
Explanation:
By Farday's Law of Electrolysis,
m = Zit
Z=96,500 coulombs,
i= 0.000025 A
t= 60 seconds.
Mass = Z * i * t
= 144.75 grams
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