Question

How many atoms of carbon are there in 18g of C6H12O6?​

Answer 1

Answer:

Thus number of molecules of carbon in 6.022∗1022 molecules of glucose must be = 6∗(6.022∗1022)=36.132∗1022 atoms of carbon.

Answer 2

Answer:

c6h12o6

molar mass =12×6+1×12+16×6=72+12+96=180

given mass =18 g

$mole = \frac{given \: mass}{molar \: mass}$

Mole =0.1

Mole of carbon atom =6×0.1=0.6

carbon atoms=6.022×10²³×0.6=3.6132×10²³