Question

How many atoms of each element are in 4Na3PO4?

3 sodium, 1 phosphorus, 4 oxygen
4 sodium, 4 phosphorus, 4 oxygen
12 sodium, 1 phosphorus, 4 oxygen
12 sodium, 4 phosphorus, 16 oxygen

Answer 1

Answer:

Explanation:

One mole of  consist of three atoms of sodium, one atom of phosphorus and four atoms of oxygen.

Now, according to question four moles of  is present. Therefore, every element present in the compound is multiply by four with their number of atoms in the compound.

So, Number of atoms of sodium in four moles of  is= 12 atoms of sodium.

Number of atoms of phosphorus in four moles of  is = 4 atoms of  phosphorus.

Number of atoms of oxygen in four moles of  is= 16 atoms of oxygen.

Hence, number of atoms of sodium is 12 , number of atoms of phosphorus is 4 and number of atoms of oxygen is 16

Thus, option (D) is the correct answer.

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Answer 2

Answer:

12 sodium, 4 phosphorus, 16 oxygen

Explanation:

One mole of $Na$ =$4$×$3$

$=12$ atoms

Similarly, one mole of $P=4$ atoms

And one mole of $O=4$×$4$

$=16$ atoms