Question

How many atoms of each element are there in 6.3 grams of nitric acid?

Answer 1

Mass of HNO3 = 1+14+3(16) = 63 g. 

No of moles = 6.3/63 = 0.1. 

=>1 mole of HNO3 has 1 mole of ( H atoms and N atoms) and 3 moles of O atoms. 

=> 0.1 mole has 0.1 moles of ( H atoms and N atoms) and 0.3 moles of ) atoms.. 

As we know 1 mole represents
$6.023 \times {10}^{23}$
particles.. 
6.3 g of HNO3 has
$6.023 \times {10}^{22}$
atoms of H ,
$6.023 \times {10}^{22}$
atoms of N,
$18.069 \times {10}^{22}$
atoms of oxygen.. 

Answer 2

Answer:

hope it will help you .....