Question

How many atoms of each element are there in 9.8g of sulphuric acid.
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Answer 1

Answer:

For H: 9.8gH2SO4(1molH2SO498gH2SO4)(2molH1molH2SO4)(6.022⋅1023atms1molH) =1.2004⋅1023 atoms / mol H.

For S: 9.8gH2SO4(1molH2SO498gH2SO4)(1molS1molH2SO4)(6.022⋅1023atms1molS) =6.022⋅1022 atoms / mol S.

For O: 9.8gH2SO4(1molH2SO498gH2SO4)(4molO1molH2SO4)(6.022⋅1023atms1molO) =2.4088⋅1023 atoms / mol O.

Answer 2

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