Question

How many atoms of each types are present in 143 gram of washing soda?

Answer 1

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Gram molecular mass of Na2CO3 = 106 g

so ,106g of Na2CO3 = 1mol

143g of Na2CO3 = 143 / 106 = 1.35 mol

Now, 1 mol of Na2CO3 contains = 2 x 6.022 x 10^23 atoms of sodium

so 1.35 mol of Na2CO3 contains = 1.35 x 2 x 6.022 x 10^23

= 16.25 x 10^23 Na atoms

1 mol of Na2CO3 contains = 6.022 x 10^23 atoms of carbon

1.35 mol would have = 1.35 x 6.022 x 10^23

= 8.13 x 10^23 carbon atoms

1 mol of Na2CO3 contains = 3 x 6.022 x 10^23 atoms of oxygen

1.35 mol would have = 1.35 x 3 x 6.022 x 10^23

= 24.39 x 10^23 oxygen atoms

Answer 2

ANSWER ☺️

Formula of washing soda=Na2co3

wt= 143

mwt is 23×2+12+16×3= 106

mole = wt/mwt

so, 143/106

no. of atom = mole× N°

then,

(143/106)× (6.023×10^23)

please solve it

N° is Avogadro no.

then no. of Atom = 8.125×10^23

HOPE it helps