Chemistry, asked by xursua4811, 1 month ago

how many atoms of helium are in 2.5 moles of helium

Answers

Answered by BEAST00757

Answer:

2.5mols of helium is present in 10g of helium.

Explanation:

023x10^23 He atoms. 1 mole Of Helium = Weight of Helium/4Weight of Helium = 1*4 = 4 grams 1 mole of Helium contains 6.023*10²³ (Avogadro number) atoms. one mole is equilant to Avogadro's number 6.02x10^23 particles.

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