How many atoms of hydrogen are present in 324g of Ca(HCO3)2
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Answer:
your answer is 2.4 * 10^24 hydrogen atoms .
Explanation:
molecular mass of ca (hco3)2 is 162 .
given mass is 324 gm
no.of moles =given mass /molecular mass
also, no. of moles =no. of molecules /avogadros no. (Na)
so, given mass * Na /molecular mass =no.of molecules
= 324*6.022*10^23/162=1.2 *10^24 molecules
Now 1 molecule of ca (hco3)2 contains 2 hydrogen atoms .
Thus 1.2 *10^24 molecule contains = 1.2 *10^24 *2 = 2.4*10^24 h-atoms
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