Question

how many atoms of hydrogen in9.8g sulphuriic acid?​

Answer 1

Answer:

H2SO4 has a mass of 98. H=1 X2 =2, S=32, O=16 X4=64' Totoal=98 grams per mole. You have 9.8g or 0.1 mole

There are 2 H , so you have .2 moles of H atoms or 6.02x 10^23 times 0.2 or 1.204 x 10^23 atoms of hydrogen

Answer 2

Explanation:

The molar mass of H_2SO_4

H

2

S

O

4

is 98 g/mol.

For H:

9.8 g H_2SO_4 ((1 mol H_2SO_4)/(98 g H_2SO_4))((2 mol H)/(1 mol H_2SO_4))((6.022*10^23 atms) / (1 mol H))

=1.2004*10^23 atoms / mol H

For S:

9.8 g H_2SO_4 ((1 mol H_2SO_4)/(98 g H_2SO_4))((1 mol S)/(1 mol H_2SO_4))((6.022*10^23 atms) / (1 mol S))

=6.022*10^22 atoms / mol S

For O:

9.8 g H_2SO_4 ((1 mol H_2SO_4)/(98 g H_2SO_4))((4 mol O)/(1 mol H_2SO_4))((6.022*10^23 atms) / (1 mol O))

=2.4088*10^23 atoms / mol O