Question

How many atoms of Na are present in 46 g of the metal?( A of Na=23)

Answer 1

Explanation:

we could solve it like

no of mole=mass/molecular weight

mass=46 g

molecular weight=23

no of moles represented as"n"

n=46/23= 2

another formula for calculating number of mole is

n= no of atoms/ Avogadro's number

n×Avogadro number= no of atoms

Avogadro's number=6.023×10^23

2×6.023×10^23= 12.046×10^23 atoms

Hope you understand it

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