Question

How many atoms of O are in 45.0g of C12H22O11

Answer 1

Answer:

6.022 × 10/23  oxygen atoms.

 

Explanation:

First, it's important to know that the chemical formula for water is  

H 2 O

. This means that one molecule of water is made of two hydrogen atoms and one oxygen atom.

Then, we need to find how many moles of water there are in  

18 g . (We need to do this, because knowing the number of moles of water will help us convert from grams to number of atoms!)

To find how many moles of water there are in  18 g , we have to divide  18 g

by the number of grams in one mole of water, also known as the molar mass of water:

number of moles  =  mass of sample

molar mass

number of moles

= 18 g

molar mass of H × 2 + molar mass of O

number of moles  = 18 g

1.008 g/mol  ×  2 + 16.00 g/mol  = 18 g  

18.02 g/mol

≈  1 mole

In  1  mole of water, there are  6.022 × 10/ 23  molecules—that's how the mole was defined!

And, since the chemical formula for water is  H 2 O ,  1 mole of water corresponds to  1  mole of oxygen atoms.

Therefore, there will be 6.022 × 10 /23  oxygen atoms in  1  mole, or  18 g  of water.