Question

How many atoms of oxygen are contained in 160 grams of N2O3?

Answer 1

Answer:

(160/

28+48) *6.022×10^23

=(160/76)*6.022×10^23

Answer 2

Answer:

There are 3.800 x $10^{24$ atoms of oxygen in one hundred sixty grams of N2O3.

Explanation:

From the above question,

To calculate the quantity of atoms of oxygen in one hundred sixty grams of N2O3.

We want to first discover the molar mass of N2O3.

The molar mass of N2O3 can be calculated by using including the atomic hundreds of nitrogen (N) and oxygen (O) in the compound:

Molar mass of N2O3

                            = two × atomic mass of N + three × atomic mass of O

                             = two × 14.01 g/mol + three × sixteen g/mol

                             = 76.03 g/mol

Now we can use the molar mass to convert the given mass of N2O3 to moles:

Number of moles = Mass / Molar mass

                             = one hundred sixty g / 76.03 g/mol

                             = 2.105 mol

The chemical method of N2O3 suggests that every molecule of N2O3 includes three atoms of oxygen.

Therefore,

         We can discover the complete variety of atoms of oxygen in 2.105 moles of N2O3 via multiplying the wide variety of moles with the aid of the quantity of oxygen atoms per molecule and Avogadro's number:

Number of oxygen atoms = 2.105 mol x three atoms/molecule x 6.022 x $10^{23$ atoms/mol

                                            = 3.800 x $10^{24$ atoms

Therefore, there are 3.800 x $10^{24$ atoms of oxygen in one hundred sixty grams of N2O3.

For more such related questions : https://brainly.in/question/20918146

#SPJ2