Question

How many atoms of oxygen are present in 200 g of caco3?

Answer 1

200 g of calcium carbonate contains oxygen atoms = 200*3*6.022*1023/100.

Answer 2

Your answer is --

firstly we find the mole of CaCO3 .

molar mass of CaCO3 = 40+12+48 = 100

Now, mol of CaCO3 = 200/100 = 2mol


Now, in CaCO3 1 mol CaCO3 contains 3 mol O .

So, 2 mol CaCO3 contains 2*3 = 6 mol O

Number of atom of O = 6*6.023*10^23 = 36.138*10^23 atom



Hence, 36.138*10^23 atoms of oxygen are present in 200 g of caco3.


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