how many atoms of oxygen are present in 300 grams of calcium carbonate.
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The formula unit mass can be calculated as :- atomic mass of :- calcium + carbon + 3 X atomic mass of oxygen = 40 +12+ 3 X 16 = 100 g.
daniya72:
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Molecular mass of calcium carbonate = 40 + 12 + 48 =100g
1 mole of Calcium carbonate contains – 3 mole of oxygen atoms
100 g of Calcium carbonate contains - 3 X 6.022 X 10∧23 oxygen atoms
300g of Calcium carbonate contains - How many oxygen atoms?
= 300 X 3 X 6.022 X 10∧23/ 100 = 54.205 X 10∧23 oxygen atoms
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