How many atoms of oxygen are present in 300g of CaCO3?
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The formula unit mass of calcium carbonate can be calculated as follows
Formula unit mass of CaCO3 = Atomic mass of calcium + atomic mass of carbon + 3 X( atomic mass of oxygen)
= 40 + 12 + 3 x (16)
= 100u
Thus the molar mass of CaCO3 (that is the mass of 6.022 X 1023 particles) is 100g. So
100g of CaCO3 = 3 X 6.022 X 1023 atoms of oxygen
1g of CaCO3 = [( 18.066 X 1023 ) / 100] atoms of oxygen
300g of CaCO3 = [(18.066 X 1023 X 300) / 100] atoms of oxygen
= 54.198 X 1023 atoms of oxygen
Formula unit mass of CaCO3 = Atomic mass of calcium + atomic mass of carbon + 3 X( atomic mass of oxygen)
= 40 + 12 + 3 x (16)
= 100u
Thus the molar mass of CaCO3 (that is the mass of 6.022 X 1023 particles) is 100g. So
100g of CaCO3 = 3 X 6.022 X 1023 atoms of oxygen
1g of CaCO3 = [( 18.066 X 1023 ) / 100] atoms of oxygen
300g of CaCO3 = [(18.066 X 1023 X 300) / 100] atoms of oxygen
= 54.198 X 1023 atoms of oxygen
maya51:
thanx
for your comment
amazing
Reported u smart guy
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