Question

→ How many atoms of oxygen are present in 44.8L Ozone
at 273 C temperature and 4 atm pressure?​

Answer 1

Answer:

At STP, number of molecules present in 22.4 L of ozone gas=6.022×1023

∴Number of molecules present in 44.8 L of ozone gas at

STP=6.022×1023×44.822.4=2×6.022×1023

∴Number of oxygen atoms present in the given volume of ozone gas=3×2×6.022×1023=3.6132×1024

[Since each molecule of ozone contains 3O-atoms].