Chemistry, asked by g9zk8zrtf2, 5 months ago

How many atoms of oxygen would be produced if you reacted 68.1 g of potassium chlorate according to the following equation: 2 KClO3 → 2KCl + 3O2

Answers

Answered by likithsunku
0

Answer:

The number of moles of KClO

3

is 6.125 g

So,

122.5

6.125

= 0.05 moles.

Two molecules of KClO

3

requires 3 molecules of O

2

Number of moles of O

2

= 3×0.05/2

= 0.075 moles

Volume of 1 mole =22.4L

Volume of O

2

= 22.480.075

= 1.68 L

Similar questions