how many atoms of phosphorous are present in 5g of it?
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Answered by
2
RAM of phosphorus is 31
So, 31 g of phosphorus contains 6.023 * 10²³ atoms of phosphorus
So, 5 g of phosphorus contains ((6.023/31)*5) * 10²³ atoms of phosphorus
So, 5 g of phosphorus contains 0.97 * 10²³ atoms of phosphorus
it can also be written as 9.7 * 10²² atoms of phosphorus
Answered by
1
0.97*10^23
Hope it’s helpful to uh
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Hope it’s helpful to uh
Mark as brainliest answer
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