Question

How many atoms of sulphur are present in 0.5 mole of SO2? ​

Answer 1

Explanation:

one mole of SO2 contain 6.023 into 10^ 23 molecules of SO2. then 0.5 mole of a SO2 contains 3.01 into 10 ^23 molecules of So2. hence 3.01*10^23 has multiply it by 3.

Answer 2

3.0115 × 10²³ number of atoms of sulfur are present in 0.5 moles of SO₂.

To Find:  

The number of atoms of sulfur present in 0.5 moles of SO₂.

Solution:

We know,

1 mole of SO₂ contains Avogadro's number ($N_{A}$) of molecules i.e,

6.023 × 10²³ number of molecules.

Therefore,

In 0.5 mole SO₂, there is,

(6.023 × 10²³ × 0.5) = 3.0115 × 10²³ number of molecules

Again, SO₂ has 1 atom of Sulfur,

which means,

the number of atoms of sulfur present in 0.5 moles of SO₂ is,

(3.0115 × 10²³ × 1) [Multiplied by 1 for 1 atom of sulfur in SO₂]

Thus, 3.0115 × 10²³ number of atoms of sulfur are present in 0.5 moles of SO₂.

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