How many atoms of sulphur are present in 64 g of SO2?
Answers
Answered by
1
Answer:6.023 ×10^23 atoms
Explanation:
No of atoms = no of moles × Avogadro number
No of moles = mass ÷ molar mass
Molar mass = 64 G
No of moles = 64÷64=1
No of atoms = 1×6.023×10^23=6.023×10^23 atoms
Answered by
1
Answer:
Molecular mass of SO2 = 1×S+2×O
= 1×32+2×16
= 32 + 32
= 64
Given mass of SO2 = 64g
Number of atoms = ?
By the formula =
N/Avagadro number = Given mass/Molecular mass
N/6.022 × 10 ^23 = 64/64
N = 6.022 × 10^23 Atoms
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