Question

How many atoms of sulphur are present in 64g of sulphur s8

Answer 1

ANSWER

Molar mass of S8 = 256.52 g/mol

Molar mass of S8 = 256.52 g/molNumber of molecules present in 256.52 g = 6.022×1023 molecules

Molar mass of S8 = 256.52 g/molNumber of molecules present in 256.52 g = 6.022×1023 moleculesNumber of molecules present in 6.4 g = 6.022×1023256.52×6.4 = 1.502 ×1022 molecules

Molar mass of S8 = 256.52 g/molNumber of molecules present in 256.52 g = 6.022×1023 moleculesNumber of molecules present in 6.4 g = 6.022×1023256.52×6.4 = 1.502 ×1022 moleculesSince 1 molecule of S8 has 8 sulphur atoms, so number of sulphur atoms in 1.502×1022 molecules is given as,

Molar mass of S8 = 256.52 g/molNumber of molecules present in 256.52 g = 6.022×1023 moleculesNumber of molecules present in 6.4 g = 6.022×1023256.52×6.4 = 1.502 ×1022 moleculesSince 1 molecule of S8 has 8 sulphur atoms, so number of sulphur atoms in 1.502×1022 molecules is given as,8× 1.502 ×1022 = 1.201×1023 atoms

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Answer 2

The molecules formula of sulphur is given to be S8 ( it Contains 8 atoms of sulphur ). So , the molecular mass of sulphur molecule is 32 × 8 = 256 u. This means that 1 mole of sulphur molecules is equal to 256 grams hope it help please mark me as brainliest