Question

how many atoms present in 300g of limestone.​

Answer 1

Explanation:

Mass of CaCO

3

= 40+12+48 = 100g

Moles of CaCO

3

=

100

300

= 3

Number of molecules of CaCO

3

= 3×6.02×10

23

1 molecule of CaCO

3

contain 3 atoms of oxygen

3×6.02×10 23 molecule will contain 3×3×6.023×10 23 =54.027×10 .23 atoms

Answer 2

Answer:

11

Explanation:

CaO is limestone

Mass of CaO is 40 + 16 = 56

So, for 56 g there are 2 atoms

So, for 300 g => 300*2/56 = 10.714

which is approx 11

Hope it helps

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