How many automatic progression with 10 terms are there whose first term is in the set 1234 and whose common difference is in the set 3 4 5 6 7?
Answers
Answered by
2
Answer:
20
Step-by-step explanation:
Arithmetic progression, AP, depends upon its first term 'A' and common difference between two consecutive terms 'D'.
Here is the formula
Tn= A*(n-i)*D
- we can choose first term in 4 ways.
- we can choose common difference in 5 ways
Total number of arithmetic progression with 10 terms whose first term is in the set {1,2,3,4} and whose common difference is in the set {3, 4, 5, 6, 7} is
4*5 =20
number of terms don't matter because it isn't in the formula.
Similar questions
Math,
7 months ago
History,
7 months ago
Computer Science,
7 months ago
Math,
1 year ago
Physics,
1 year ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago