Question

how many avogadro number (n) is present in 54kg water molecules​

Answer 1

$\huge\mathfrak\pink{answer}$

There are 6.022×1023 molecules in a mole. There are 18.01528 grams of water per mole of water.

Answer 2

Answer:

We get 1.81×10

24

water molecules...

Explanation:

We assess the molar quantity of water in the usual way...

Number of moles=

molar mass

mass ≡ 18.01⋅g⋅mol −1

54⋅g =3.00⋅mol

But the mol is like the dozen or the gross, it specifies a NUMBER, here N

A ≡6.022×10

23 ⋅mol. Why do we use such an absurdly large number? Because N

A

⋅1H⋅atoms have a MASS of 1⋅g precisely...and thusthe mole is the link between the micro-world of atoms, and molecules, to the macro world of grams and litres....

And so (finally!) we take the product...

Number of water molecules=molar quantity×Avogadro’s number.

= a number as required..

3.00⋅mol×6.022×10

23 ⋅mol −1=??⋅water molecules