how many ball of radius 0.5 cm can be prepared by melting a metal cylindrical with radius 4cm and height 3cm?
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volume of cylinder= n× volume of each ball
π*4^2*3= n*4/3*π*0.5^3
48 = n*4*0.125/3
n = (48*3)/(4*0.125)= 288 balls
π*4^2*3= n*4/3*π*0.5^3
48 = n*4*0.125/3
n = (48*3)/(4*0.125)= 288 balls
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