Question

How many Beta glycosidic bond present in DNA segment of 68nm length ​

Answer 1

Explanation:

756 003 6518

12345

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Answer 2

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• As the average length of a nucleotide is 3.4 Angstrom hence there are 200 nucleotides present in 68 nm long DNA. 2 nucleotides form a base pair hence 100 base pairs are present. Adenine-Thymine forms a base pair with a double hydrogen bond and Guanine-Cytosine form base pair with a triple bond.

• According to the question, 25% of this DNA molecule consists of Adenine which means that equal percent of Thymine is present as well forming 50% DNA as Adenine-Thymine base pair ( 50 base pairs) While Rest of the 50% DNA consists of Guanine -Cytosine ( 50 base pairs ).

• Based on this number of hydrogen bonds present are -2*50 + 3*50 = 250.