How many bits can fit on a link with a 2 ms delay if the bandwidth of the link is
a. 1 Mbps?
h. 10 Mbps?
c. 100 Mbps?
Answers
Answered by
4
Answer:
Number of bits sent through a channel depends on the bandwidth and the delay caused due to the channel. Therefore number of bits = bandwidth*delay. When the bandwidth of the channel is 1Mbps = 106bps. Therefore the number bits that can be sent using the link are 2000 bits when the bandwidth is 1 Mbps.
Answered by
1
Answer:
Correction to @ka4756625 answer:
Number of bits sent through a channel depends on the bandwidth and the delay caused due to the channel.
Therefore, number of bits = bandwidth * delay.
When the bandwidth of the channel is 1Mbps = 10 ^ 6 bps.
Number of bits for 1Mbps = 1 Mbps x 2 ms = (1 x 10^6) x (2 x 10^-3) = 2000 bits
Similar questions