Question

How many bits can fit on a link with a 2 ms delay if the bandwidth of the link is

a. 1 Mbps?

h. 10 Mbps?

c. 100 Mbps?

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Answer 1

Answer:

Number of bits sent through a channel depends on the bandwidth and the delay caused due to the channel. Therefore number of bits = bandwidth*delay. When the bandwidth of the channel is 1Mbps = 106bps. Therefore the number bits that can be sent using the link are 2000 bits when the bandwidth is 1 Mbps.

Answer 2

Answer:

Correction to @ka4756625 answer:

Number of bits sent through a channel depends on the bandwidth and the delay caused due to the channel.

Therefore, number of bits = bandwidth * delay.

When the bandwidth of the channel is 1Mbps = 10 ^ 6 bps.

Number of bits for 1Mbps = 1 Mbps x 2 ms = (1 x 10^6) x (2 x 10^-3) = 2000 bits