How many boat parties of 8, consisting of 5 boys and 3 girls, can be made from 25 boys and 10 girls? how many boat parties of 8, consisting of 5 boys and 3 girls, can be made from 10 boys and 25 girls?
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Answer:
6375600 no. of different boat parties of 8, consisting of 5 boys and 3 girls, can be made
Step-by-step explanation:
10
C
3
Formula :^nC_r=\frac{n!}{r!(n-r)!}
n
C
r
=
r!(n−r)!
n!
So, No. of different boat parties =\frac{25!}{5!(25-5)!} \times \frac{10!}{3!(10-3)!}=6375600
5!(25−5)!
25!
×
3!(10−3)!
10!
=6375600
Hence 6375600 no. of different boat parties of 8, consisting of 5 boys and 3 girls, can be made
#Learn more :
How many different pairs of 1 boy and 1 girl each can possibly be formed from 4 girls and 3 boys?
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