Question

How many boxes can be accommodated in a cubic godown of length 17 m if each box
requires 3.4 cu m of space? The boxes are placed in the room without leaving any space
between them.​

Answer 1

Answer: 25 boxes

Step-By-Step Explanation:area of godown = 17*17=289

area of boxes = 3.4*3.4=11.56

no. of boxes = 289/11.56=25 boxes

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Answer 2

1445 boxes can be placed in the room.

Step-by-step explanation:

Consider the provided information.

The cubic godown of length 17 m.

Find the volume of the cubic godown by using the formula: $V=l^3$

$V=17^3\\V=4913$

Hence, the volume of the godown is 4913 m³.

It is given that the volume of the box is 3.4 m³.

To find the number of boxes that can be accommodated divide 4913 by 3.4

Number of boxes can be placed = $\frac{4913\ m^3}{3.4\ m^3} =1445$

Hence, 1445 boxes can be placed in the room.

#Learn more

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