Question

How many boxes can be accommodated in a cubic godown of length 17m if each box requires 3.4cu m of space? The boxes are placed in the room without leaving any space between them.​

Answer 1

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Answer:

1,445 boxes

Step-by-step explanation:

Length of Godown = 17 m

∴ Volume of godown = $Length^{3}$

                                    = $17^{3}$

                                    = 4,913 $m^{3}$

Volume of 1 box = 3.4 $m^{3}$

∴ Number of boxes = $\frac{Volume of godown}{Volume of 1 box}$

                                 = $\frac{4913}{3.4}$

                                 = $\frac{49130}{34}$

                                 = 1,445 boxes

                               

Answer 2

Answer:

Here is your answer .

Step-by-step explanation:

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