Question

How many boxes, each of size 12 cm × 8 cm × 6 cm can be packed in a carton of size 60 cm × 48 cm × 36 cm? ​

Answer 1

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Answer 2

$\large{\boxed{\rm{\orange{Question:-}}}}$

$How \: many \: boxes \: , each \: of \: size \: 12 cm × 8 cm × 6 cm \: can \: be \: packed \: in \: a \: carton \: of \: size \: 60 cm × 48 cm × 36 cm?$

$\large{\boxed{\rm{\orange{To\: find:-}}}}$

$Number \: of \: boxes.</p><p>$

$\large{\boxed{\rm{\orange{Solution:-}}}}$

$Size \: of \: each \: box \: is \: ( 12 cm × 8 cm × 6 cm )$

$∘ Length \: of \: the \: box = 12 cm, \\ \: \:breadth \: of \: the \: box = 8 cm, \: \\ Height \: of \: the \: box = 6 cm$

$∘ Volume \: of \: 1 \: box = ( 12×8×6 ) \: cubic \: cm$

$Size \: of \: each \: carton = ( 60cm ×48cm ×36cm )$

$∘ Length \: of \: each \: carton = 60 cm,</p><p> \\ Breadth \: of \: each \: carton = 48 cm,</p><p> \\ Height \: of \: each \: carton = 36 cm.$

$∘ Volume \: of \: each \: carton = ( 60×48×36 ) cubic \: cm.$

$Required \: number \: of \: boxes = \frac{volume \: of \: 1 \: carton}{volume \: of \: 1 \: box}$

$= \frac{(60 \times 48 \times 36)}{(12 \times 8 \times 6)}$

$= 180$

$\large{\boxed{\rm{\orange{Additional\: information:-}}}}$

• $The \: measure \: of \: the \: amount \: of \: space \: enclosed \: by \: a \: solid \: is \: called \: its \: volume.$
• $Volume \: of \: a \: cubiod = (length \times breadth \times heigth) \: cubic \: units$
• $Volume \: of \: a \: cube = (side\times side\times side) \: cubic \: units$