How many bricks, each 22 cm long and 15 cm broad, will be required to pave a court 30 m long and 22 m wide?
Answers
Answer : - 20000
Step-by-step explanation:
Given:-
Length of the brick surface = L1 =22 cm
Breadth of the brick surface= B1 = 15 cm.
Length of court =L2 = 30 m = 3000 cm.
..................(Since, 1m = 100cm.)
Breadth of the Court = B2 = 22m =2200 cm
..................(Since, 1m = 100cm.)
Assuming the surface of the brick as rectangle,
...................(Surface of a cuboid)
Area of rectangle = L x B
Therefore,
Area of each brick's surface = L1B1
Area of court = L2B2
No of bricks required = Area of court ÷ area of each brick
=L2B2 ÷ L1B1
=3000 x 2200 ÷ 22 x 15
=200 x 100 .......(simplify)
= 20000
Therefore, 20000 bricks would be required to pave the court.
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