Question

How many bricks, each 22 cm long and 15 cm broad, will be required to pave a court 30 m long and 22 m wide?​

Answer 1

Given :

• Length of the brick = 22cm
• Breadth of the brick = 15cm
• Length of the court = 30m
• Breadth of the court = 22m

To find :

• Number of bricks required to pave a court 30 m long and 22 m wide.

Solution :

$\sf~\to~Area~ of~ the ~brick = Length \times Breadth$

$\sf~\to~Area~ of~ the ~brick = 22 \times 15$

$\sf~\to~Area~ of~ the ~brick = 330~sq.cm$

Now,

$\sf~\to~Area ~of~ the~ court = Length \times Breadth$

$\sf~\to~Area ~of ~the ~court = 30 \times 22$

$\sf~\to~Area ~of ~the~ court = 660~sq.m$

Converting area of the court (660 sq.m) into sq.cm :

We know,

$\sf~~~~~~~1~m=100~cm$

Therefore,

$\sf~~~~~~~660~m=66000~cm$

$\sf~~~~~~~660~sq.m=6600000~sq.cm$

Finally,

$\sf\twoheadrightarrow\:No.~of~bricks~=\frac{Area~of~court}{Area~of~each~brick}$

$\sf\twoheadrightarrow\:No.~of~bricks~=\cancel{\frac{6600000}{330}}$

$\sf\twoheadrightarrow~No.~of~bricks~=20000$

$\bf~Therefore,$

$\bf~~~~~~~~~~~The~number~of~brick~required~is~20000.$

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