Question

How many bricks, each measuring 25 cm x 15 cm x 8 cm will be required to build a wall of dimensions 10 m x 4 m x 5 m, if $\frac {1}{10}$th of its volume is occupied by a
mortar?​

Answer 1

Step-by-step explanation:

Given:

The dimension of Wall = 10 m × 4 m × 5 m

Dimension of a brick = 25 cm × 15 cm × 8 cm

Formula used:

The volume of the cuboid = Length × breadth × height

1m = 100 cm

Concept Used:

To find out the number of bricks, we divide the volume of the wall by the volume of a brick.

Calculation:

The volume of Brick = 25 cm × 15 cm × 8 cm = 3× 103 cubic cm

The volume of Wall = 10 m × 4 m × 5 m = 200 cubic m = 2 × 108 cubic cm

According to the question,

10% of its volume is occupied by mortar, then

The volume of Wall with bricks = 90% × 2 × 108 cubic cm.

The number of bricks = {90% × (2 × 108)}/(3× 103)

⇒ 60000.

∴ The number of bricks required to construct the wall is 60000.