Math, asked by mahimbvbvpn1396, 9 months ago

How many bricks of dimensions 24 cm × 12 cm × 8 cm are required to make a wall 10 m long, 4 m high and 36 cm thick?

Answers

Answered by MisterIncredible
5

Question :-

How many bricks of dimensions 24cm x 12cm x 8cm are required to make a wall of 10m long , 4m high, 36 cm thick ?

Answer :-

Given :-

Dimensions of the brick is 24cm x 12cm x 8cm

Dimensions of the wall is 10m x 4m x 36cm

Required to find :-

  • Number of bricks required ?

Units Conversion :-

Before solving this question we need to convert some units from one unit to another .

Here, we have to change the dimensions of the brick from cm to meters similarly the thickness of the wall should also be converted .

So,

Dimensions of the brick = 24cm x 12cm x 8cm

we know that

\tt{ 1 \; centimetre = \dfrac{1}{100} meters }

So,

24cm = 24/100 = 0.24 m

12cm = 12/100 = 0.12 m

8cm = 8/100 = 0.08 m

Similarly,

Thickness of the wall = 36cm

=> 36cm = 36/100 = 0.36 m

Formula used :-

\leadsto{\boxed{\textsf{Volume of a cuboid }{\mathsf{\;= length \times Breadth \times Height }}}}

Solution :-

Given :-

Dimensions of the brick = 0.24m x 0.12m x 0.08m

So,

Length of the brick = 0.24 m

Breadth of the brick = 0.12 m

Height of the brick = 0.08 m

By using the formula ,

\leadsto{\boxed{\textsf{Volume of a cuboid }{\mathsf{\;= length \times Breadth \times Height }}}}

➜ volume of the brick = 0.24 m x 0.12 m x 0.08 m

➜ Volume of the brick = 0.002304 m³

Similarly,

We are also given with,

Dimensions of the wall = 10 m x 4 m x 0.36 m

So,

Length of the wall = 10 m

Breadth of the wall = 4 m

Height of the wall = 0.36 m

➜ Volume of the wall = 10 m x 4 m x 0.36 m

➜ Volume of the wall = 14.4 m³

Now we have to find the number of bricks required .

So,

No. of bricks required is equal to Volume of the wall by Volume of the brick .

\tt{No. \; of \; bricks \; required = \dfrac{Volume \; of \; the Wall}{Volume\; of \; the \: brick }}

So,

\longrightarrow{\tt{ No. \; of \; bricks \; required = \dfrac{14.4 \; m^3 }{0.002304 \;m^3 }}}

➜ m³ get cancelled in both numerator and denominator

\longrightarrow{\tt{No. \; of \; bricks \; required = \dfrac{14.4 }{0.002304 }}}

➜ Multiply numerator and denominator with 10,00,000

\leadsto{\tt{No.\; of \;bricks \; required = \dfrac{1,44,00,000}{2304}}}

\implies{\red{\tt{ No. \; of \; bricks \; required = 6,250\; bricks }}}

\large{\leadsto{\tt{\therefore{No. \; of \; bricks \; required = 6,250 \; bricks }}}}

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