Question

how many bricks of dimensions 9cm×6cm×4cm will be required to build a cubical structure of side 60cm​

Answer 1

Answer:

1000 bricks

Step-by-step explanation:

l = 9cm

b = 6cm

h = 4cm

side of the cube = 60 cm

volume of cuboid = volume of cube

let n be the number of bricks

l x b x h x n = $l^{3}$

9 x 6 x 4 x n = $60^{3}$

n = $\frac{60 * 60 * 60}{9 * 6 * 4}$

n=$\frac{216000}{216}$

n= 1000

therefore bricks required are 1000

Answer 2

Answer:

10000 bricks

Step-by-step explanation:

volume of a single brick is (9×6×4)cm^3

= 216cm^3

now total volume of cuvical structure is (60^3)cm^3

= 216000 cm^3

no. of bricks required =

volume of structure/volume of single brick

= 2160000

216

= 10000 bricks