How many bricks of length=18cm, breadth=10cm and height(thickness)=8cm will be needed to built a wall of length=12m, thickness=8cm and height=2.4m (Want Solved)
Answers
GIVEN:-
- Length of brick= 18cm
- Breadth of brick = 10cm
- Height of brick = 8cm
- Length of wall = 12m
- Breadth of wall = 8cm
- Height of wall= 2.4m
SOLUTION:-
Now, Volume of Wall =LBH
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GIVEN:-
Length of brick= 18cm
Breadth of brick = 10cm
Height of brick = 8cm
Length of wall = 12m
Breadth of wall = 8cm
Height of wall= 2.4m
\green\bigstar★ SOLUTION:-
\implies\sf \: volume \: of \: cubodial \: brick = l \times b \times h⟹volumeofcubodialbrick=l×b×h
\implies\sf \: volume \: of \: cubodial \: brick = 18 \times 10 \times 8⟹volumeofcubodialbrick=18×10×8
\implies\sf \: volume \: of \: cubodial \: brick = 1440 \: cm ^{2}⟹volumeofcubodialbrick=1440cm2
\implies\sf \: volume \: of \: cubodial \: brick = 14.40 {m}^{2}⟹volumeofcubodialbrick=14.40m2
Now, Volume of Wall =LBH
\implies\sf \: volume \: of \: cubodial \: wall = 12 \times 800 \times 2.4⟹volumeofcubodialwall=12×800×2.4
\implies\sf \: volume \: of \: cubodial \: brick = 230400m \:⟹volumeofcubodialbrick=230400m
\bf \red{ \leadsto \: number \: of \: bricks \: required = \blue{ \dfrac{ \sf \: volume \: of \: cubodial \: wall}{ \sf \: volume \: of \: cubodial \: brick } }}⇝numberofbricksrequired=volumeofcubodialbrickvolumeofcubodialwall
\bf \red{ \leadsto \: number \: of \: bricks \: required = \blue{ \dfrac{ 230400}{ 14.4} }}⇝numberofbricksrequired=14.4230400
\boxed{ \bf \red{ \leadsto \: number \: of \: bricks \: required }= \blue{1600}}⇝numberofbricksrequired=1600