Math, asked by anshika6867, 4 months ago

How many bricks of length=18cm, breadth=10cm and height(thickness)=8cm will be needed to built a wall of length=12m, thickness=8cm and height=2.4m (Want Solved)

Answers

Answered by TheCommander
10

\red\bigstar GIVEN:-

  • Length of brick= 18cm
  • Breadth of brick = 10cm
  • Height of brick = 8cm
  • Length of wall = 12m
  • Breadth of wall = 8cm
  • Height of wall= 2.4m

\green\bigstar SOLUTION:-

  \implies\sf \: volume \: of \: cubodial \: brick = l \times b \times h

 \implies\sf \: volume \: of \: cubodial \: brick = 18 \times 10 \times 8

 \implies\sf \: volume \: of \: cubodial \: brick = 1440 \: cm ^{2}

 \implies\sf \: volume \: of \: cubodial \: brick = 14.40 {m}^{2}

Now, Volume of Wall =LBH

 \implies\sf \: volume \: of \: cubodial \: wall = 12 \times 800 \times 2.4

 \implies\sf \: volume \: of \: cubodial \: brick = 230400m \:

 \bf \red{ \leadsto \: number \: of \: bricks \: required =  \blue{ \dfrac{ \sf \: volume \: of \: cubodial \: wall}{ \sf \: volume \: of \: cubodial \: brick } }}

 \bf \red{ \leadsto \: number \: of \: bricks \: required =  \blue{ \dfrac{ 230400}{ 14.4} }}

 \boxed{ \bf \red{ \leadsto \: number \: of \: bricks \: required }=  \blue{1600}}

Answered by Anonymous
2

Mark above answer as brainliest!!!!!!

GIVEN:-

Length of brick= 18cm

Breadth of brick = 10cm

Height of brick = 8cm

Length of wall = 12m

Breadth of wall = 8cm

Height of wall= 2.4m

\green\bigstar★ SOLUTION:-

\implies\sf \: volume \: of \: cubodial \: brick = l \times b \times h⟹volumeofcubodialbrick=l×b×h

\implies\sf \: volume \: of \: cubodial \: brick = 18 \times 10 \times 8⟹volumeofcubodialbrick=18×10×8

\implies\sf \: volume \: of \: cubodial \: brick = 1440 \: cm ^{2}⟹volumeofcubodialbrick=1440cm2

\implies\sf \: volume \: of \: cubodial \: brick = 14.40 {m}^{2}⟹volumeofcubodialbrick=14.40m2

Now, Volume of Wall =LBH

\implies\sf \: volume \: of \: cubodial \: wall = 12 \times 800 \times 2.4⟹volumeofcubodialwall=12×800×2.4

\implies\sf \: volume \: of \: cubodial \: brick = 230400m \:⟹volumeofcubodialbrick=230400m

\bf \red{ \leadsto \: number \: of \: bricks \: required = \blue{ \dfrac{ \sf \: volume \: of \: cubodial \: wall}{ \sf \: volume \: of \: cubodial \: brick } }}⇝numberofbricksrequired=volumeofcubodialbrickvolumeofcubodialwall

\bf \red{ \leadsto \: number \: of \: bricks \: required = \blue{ \dfrac{ 230400}{ 14.4} }}⇝numberofbricksrequired=14.4230400

\boxed{ \bf \red{ \leadsto \: number \: of \: bricks \: required }= \blue{1600}}⇝numberofbricksrequired=1600

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