Question

how many bricks require contract of wall is 20m long, 80cm height and 6m breadth. If each bricks major length,breadth ,and height is5cm, 25cm, and 10cm.

Answer 1

$<b>$ Solution

Given :-

measure brick

length = 5cm

breadth = 25cn

height = 10 cm

volume of brick = (length *breadth*height)

volume of brick = ( 5*25*10)

volume of brick = 1250cm³

Then we find require contract of brick

length = 20 m

1m = 100 cm

20 * 100 = 2000cm

breadth = 80cm

height = 6m

1m. = 100 cm

6*100 = 600 cm

we use volume = L* B*H

volume = 2000* 80* 600

Volume = 96000,000 cm³

No bricks required = 96000,000/ 1250

Bricks required = 76,800

Answer = 76,800

Answer 2

$\: \: \: \: \: \: \color{green}\huge \bf{holla \:m ate}$
$\underline{ \bf{QUESTION}} : \\ \\ \tiny \bf{how \: many \: bricks \: require \: contract \: of \: wall \: is \: 20m \: long, \: 80cm } \\ \tiny\bf { height \: and \: 6m \: breadth.} \\ \tiny \bf{ If \: each \: bricks \: major \: length \: ,breadth \: ,and \: heigh t \: is \: 5cm}, \\ \tiny \bf{ 25cm, \: and \: 10cm.} \\ \\ \underline{ \bf{ SOLUTION}} : \\ \\ \small\bf{first \: arrange \:the \: volume \: of \: wall \rightarrow} \\ \\ \rightarrow \tiny\bf{l = 20m = 2000cm, \: h = 80cm,b = 6m = 600cm} \\ \\ \rightarrow \frak{2000 \times 80 \times 600 = 96,000,000}\\ \bf{the \: volume \: of \: wall \: is \: 96,000,000cm ^{3} } \\ \\ \rightarrow \bf{now \: the \: volume \: of \: each \: bricks } \\ \\ \huge \underline{\bf{given}} : \\ \\ \bf{l = 5cm,b = 25,h = 10} \\ \\ = > \frak{5 \times 25 \times 10 = 1250} \\ \\ \tiny \bf{then, \: total \: bricks \: = \frac{the \: volume \: of \: the \: wall}{the \: volume \: of \: each \: bricks} } \\ \\ = > \frac{ \frak{96,000,000}}{ \frak{1250 }} = \frak{76,800} \\ \\ \tiny\bf{the \: total \: bricks \: required \: to \: construct \: a \: wall \: are \: \frak{76800} }$