Math, asked by Ellojiii1, 1 month ago

how many bricks will be required for a wall which is 8m long ,6 m high and 22.5 cm thick, if each brick measures 25 cm × 11.25 cm × 6cm?​

Answers

Answered by misscuteangel
41

GIVEN :

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↪ \sf  \: length \:  = 8 \: m

↪ \sf breadth \:  = 22.5 \: m

↪ \sf \: height  = 6 \: m

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SOLUTION :

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 ↪ \sf \: length \: of \: the \: wall = (8 \times 100)cm = 800 \: cm

↪ \sf \: breadth \: of \: the \: wall = 22.5 \: cm

↪ \sf \: height \: of \: the \: wall = (6 \times 100)cm = 600 \: cm

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FORMULA :

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 \sf↪ \: volume \: of \: the \: wall = (l \times \: b  \times h)

↪ \sf \: volume \: of \: the \: wall = (800 \times 22.5 \times 600)cm ^{3}

 ↪ \sf \: volume \: of \: 1 \: brick = (25 \times 11.25 \times 6)cm ^{3}

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NUMBER OF BRICKS

REQUIRED :

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↪ \sf \:  =  \dfrac{volume \: of \: the \: wall}{volume \: of \: one \: brick}  = ( \dfrac{800 \times 22.5 \times 600}{25 \times 11.25 \times 6} )

↪ \sf \: = 6400

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 {\boxed {\red {\sf{Hence  \: 6400 \: bricks \: will \: be \: required \: for \: a \: wall.\: }}}}

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 \huge \frak \pink{@misscuteangel}

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