Question

How many bricks will be required to build a wall of 8m long , 6m height and 22.5 cm thick, if each brick measures 25 cm by 11.25 cm by 6 cm

Answer 1

Answer:

Step-by-step explanation:

Given :-

Dimensions of Wall :-

• Length of wall = 8 m
• Height of wall = 6 m
• Width of wall = 22.5 m

Dimensions of bricks :-

• 25 cm × 11.25 cm × 6 cm

To Find :-

• Number of bricks

Solution :-

$\sf \implies Volume \: of \: one \: brick = (25 \times 11.25 \times 6) cm^3\\\sf \implies Volume \: of \: the \: wall = (800 \times 600 \times 22.5) cm^3$

$\sf \implies Number \: of \: bricks =\frac{Volume \: of \: the \: walls}{Volume \: of \: one \: brick}\\ \sf \implies Number \: of \: bricks = 800 \times 600 \times 22.5 / 25 \times 11.25 \times 6\\\bf \implies Number \: of \: bricks = 6400$

Hence, 6400 bricks will be required to build a wall.

Answer 2

$\large\underline{ \underline{ \: \sf Solution : \: \: \: }}$

Given ,

$\huge \star$Dimensions of wall are :

Length = 8 m = 800 cm

Thickness = 22.5 cm

Height = 6 m = 600 cm

$\huge \star$Now , each brick is a cuboid with

Length = 25 cm

Breadth = 11.25 cm

Height = 6 cm

$\to \sf Volume \: of \: one \: brick = (25 × 11.25 × 6) \: {cm}^{3} \\ \\ </p><p></p><p> \to \sf Volume \: of \: the \: wall = (800 × 600 × 22.5) \: {cm}^{3}$

$\to \sf Number \: of \: bricks = \frac{Volume \: of \: the \: walls}{Volume \: of \: one \: brick } \\ \\</p><p> \to \sf </p><p>Number \: of \: bricks = \frac{800 × 600 × 22.5}{25 × 11.25 × 6} \\ \\ </p><p> \to \sf </p><p>Number \: of \: bricks = 6400$

Hence , the wall requires 6400 bricks