Math, asked by ashwink46851, 1 year ago

How many bricks will be required to lay a path 120 m long and 2.4 m if a brick is 24 cm long and 15 cm wide?

Answers

Answered by SnowySecret72
76

Answer:

8000 bricks

Solution:-

Length of the path=120m

In cm

120×100=12000 cm

Breadth of the path=2.4m

In cm

2.4×100=240 cm

Now,Area of Path=length×breadth

=12000 cm ×240 cm

=28,80,000 cm^2

Length of the brick=24 cm

Breadth of the brick=15 cm

Area of brick=24 cm×15 cm

=360 cm^2

Number of brick required

 \frac{area \: of \: path}{area \: of \: brick}

 \frac{2880000}{360}

8000

--------------------

Number of brick required to lay a path=8000

--------------------------------------[ANSWER]

Answered by himanshu57701
43

Answer:

8000 brick's

Step-by-step explanation:

path length=120m

path width=2.4m

path area=length×width =288m

brick length=24cm=.24m

brick width=15cm=.15

brick area=length ×width=.0360m

Now, Number brick's = area of path / area of brick= 8000

Similar questions